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gizmo_the_mogwai [7]
3 years ago
13

When the numbers used to estimate are less than the actual numbers provided, the product will be?. Single choice.

Mathematics
2 answers:
ss7ja [257]3 years ago
7 0
Underestimate because the dude said so
Inga [223]3 years ago
4 0

Answer:

Underestimate  It says when nubers are used to estimate less so it would be underastimate

Step-by-step explanation:

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Mary moves 3 steps backward as she dances​
IgorLugansk [536]
Where’s the question????
3 0
2 years ago
3) The average age of students at XYZ University is 24 years with a standard deviation of 8 years. Number of students at the uni
otez555 [7]

Answer:

0.1875

Step-by-step explanation:

σM=σ/√N

=8/√7500

=8/86.608

=0.092

Z=(x-μ)/σ/√N

=(25.5-36)/8/√7500

=-10.5/0.0092=-1141.304

Z score = -1.3125

=(27-36)/8/√7500 =

=9/0.0092=978.261

Z score= -1.125

-1.125-(-1.3125)=-1.125+1.3125)= 0.1875

The probability that the sample mean will be between 25.5 and 27 years

P(between 25.5 and 27) = 0.1875

3 0
2 years ago
Determine the value of the variable. 5 + 17 = J - 14
Nataly_w [17]
You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36
3 0
2 years ago
Read 2 more answers
2,000 +3,500+4,000+6,000+10,000=what
kvv77 [185]

Answer:

25500

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please help me answer this question ASAP! If you give me a stupid answer I will report your account
VladimirAG [237]

Answer:

B

Step-by-step explanation:

It is linear.

We can see the right side are multiples of 3. So the equation so the table is:

c = 3h

When h = 5   c = 15

c = 3h

c = 3*5

c = 15

When h = 12   c = 36

c = 3h

c = 3*12

c = 36

The constant rate of change between cost and time is 3.

Another way to solve is check for rate of change using 2 points on the chart.

Let's choose h = 5 c = 15      and h = 12 c = 36

The normal equation for rate of change is:

m = \frac{y_{2} -y_{1}}{x_{2}-x_{1}}  in this case we have h and c so:

\frac{c_{2} -c_{1}}{h_{2}-h_{1}}

h₁ = 5       h₂ = 12

c₁ = 15      c₂ = 36

So:

\frac{c_{2} -c_{1}}{h_{2}-h_{1}} = \frac{36 -15}{12-5} = \frac{21}{7} = \frac{3}{1} =3

Now that we know it's 3 we use slope intercept form to find the equation.

y = mx + b        ( m = 3) and we plug in a point to find b.

y = 3x + b          h = 5 (x)      c = 15 (y)

15 = 3(5) + b     Solve for b.

15 = 15 + b        Subtract 15 from each side.

15 - 15 = 15 - 15 + b

0 = b                 b is 0 showing our equation was correct.

y = 3x   or    c = 3h

6 0
2 years ago
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