Answer:
(a) a ≈ 22.7 meters, (b) c ≈ 10.6 meters, (c) ∠A = 65°
Step-by-step explanation:
assuming side a/c is side BC/AB since it's opposite of angle A/C
(a) SOH CAH<em>(cos = </em><em>adjacent side/hypotenuse</em><em>)</em> TOA
=> cos (25°) = BC/AC or a/b
=> cos (25°) = a/25
=> a = cos (25°) × 25
=> a ≈ 22.7
(b) SOH<em>(sin = </em><em>opposite side/hypotenuse</em><em>)</em> CAH TOA
=> sin (25°) = AB/AC or c/b
=> sin (25°) = c/25
=> c = sin (25°) × 25
=> c ≈ 10.6
(c) 180° - 25° - 90°(the right angle) = 65°
Answer:
Step-by-step explanation:
=2(9) + 21 + 2. =18+ 23. =41. 41. H. 5b²-2b+1 solve when b= -3. Substitute b with – 3 and solve. 3). A. 783. 5(-3)2-2(-3)+1. =5(9)+6+1. =45+7. =52. Move the x with the ... 3x*x? 2yºy? (8x – 2)+(7 – 3x). _ + 8x – 2. - 3x + 7. 5x +5. =5x+5. = 5(x+1). Next, factor ... 8. 8. (x − 2)(3 – x). (x − 3)(x + 5). _ (x − 2)(x – 3)(-1). (x − 3)(x + 5).
The equation of line that passes through the point(5,-3) and is parallel to the line 4x-5y=45 is:
Step-by-step explanation:
Given equation is:
First of all we have to convert the equation in slope-intercept form
So,
Let m1 be the slope of given line and m2 be the slope of required line
The coefficient of x is the slope of the line, so
m1 = 4/5
As the required line is parallel to given line, both will have equal slopes
m2 = 4/5
Slope-intercept form is:
Putting the value of m2
Putting the point (5,-3) in the equation
Putting the value of b
Hence,
The equation of line that passes through the point(5,-3) and is parallel to the line 4x-5y=45 is:
Keywords: Slope, equation of line
Learn more about equation of line at:
#LearnwithBrainly