1) Opposite angles in a quadrilateral add up to 180 degrees. Thus, the opposite angle would be 180 - 82, which would be 98 degrees.
2) It would be approximately 90 degrees, as it is a quarter of a 360 degree circle (360 / 4).
I think it is B (don't take me for certain cuz I don't know)
Here you go:
h = 5 x 2.54
please correct me if I'm wrong,
Hope it helps!
=3/10 / 7/18
=3/10*18/7
=54/70
=27/35
Answer:
m∠C = 66°
Step-by-step explanation:
Since AB = BD, it means this triangle is an Isosceles triangle and as such;
∠BAD = ∠BDA = 24°
Thus, since sum of angles in a triangle is 180,then;
∠ABD = 180 - (24 + 24)
∠ABD = 180 - 48
∠ABD = 132°
We are told that BC = BD.
Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC
Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.
Thus;
132 = ∠BCD + ∠BDC
Since ∠BCD = ∠BDC, then
∠BCD = ∠BDC = 132/2
∠BCD = ∠BDC = 66°
