Answer: A' should be at (-2, -2); D' should be at (4,-2). Good luck!
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Answer:
Step-by-step explanation:
I don't see any information on dimensions of the cans or box, so I'll assume the question wants a general solution.
Three steps will result in the volume of sand required to fill the remaining space in the box.
1. Calculate the volume of a can using the equation for the volume of a cylinder: Vol = πr²h
2. Multiply the can volume by 12. This will give the total volume of the 12 cans in the box.
3. Calculate the volume of the box: Volume = (Base)(Width)(Height)
[Make sure the units are the same as those used in calculating the can volume. E.g., if the can is calculated with cm as the measue, the box dimensions must also be cm]
4. Subtract the volume of the12 cans (from step 2) from the volume of the box.
The result from 4 will be the volume of sand required to fill the box containing 12 cans.
I'm not clear why filling the box with sand is important, but perhaps it will absorb any soda released from cans broken when the heavy box is dropped by the person shocked that 12 cans of pop could be so heavy.
Answer:
9.5
Step-by-step explanation:
You would need to do 9.5 assignments a day if you want to destribute the work load evenly among the 6 days.
57/6 = 9.5
Hope this helps
F(x) = 5(-3x) ^2 - (-3x) + 1
f(x) = -8x ^2 + 3x + 1
f(x) = -8x ^3 + 3x
for the first truck 1680 / 14 = 120 liters used
the second 1680 / 12 = 140 litres used
so 140-120 = 20 liters <span>the second truck used more </span>
