Wasting my last points on this please help me out guys
1 answer:
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Answer:
Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:
Where and
We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean is given by:
And for this case the standard error would be:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:
Where and
We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean is given by:
And for this case the standard error would be:
Answer:
0.0001042
Step-by-step explanation:
Power of tens rule states that if the denominator of a fraction has the positive power of 10, decimal in the numerator will be shifted to the left by the same number of places as exponent.
10⁴) 1.042 =
In the denominator of the given fraction, exponent of 10 = +4
So the decimal in numerator will be shifted left by 4 places.
Therefore, answer is 0.0001042