All categories

3 years ago

Examples of repeating decimals

2 answers:

7 0

1)1.2bar on top of 2 this sign. _ but on the top
2)2.3 bar on 3
3)4.6bar on 6
4)5.9 bar on 9
5)6.3 bar on 3
A bar on a number means that number is repeated infinitely

Aliun [14]3 years ago

3 0

6.66, with a bar on top of the last two sixes

You might be interested in

2. Find the distance between the two points on the coordinate plane given below.

Alex_Xolod [135]

The answer to this is 5

5 0

3 years ago

Hi sydney I need help

zvonat [6]

I am not Sydney, but I hope I can answer this question. We know that one sign equals 6 movies, so 18/6=3. B would be your answer.

5 0

3 years ago

Read 2 more answers

Find the percent change 10 inches to 25 inches

svp [43]

Answer:

NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Cystic fibrosis (CF) is a hereditary lung disorder that often results in death. It can be inherited only if both parents are car

OLEGan [10]

Answer:

0.9959 = 99.59% probability that a randomly chosen person of European ancestry does not carry an abnormal CF gene given that he /she tested negative.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Tested negative

Event B: Does not carry an abdornal CF gene.

Probability of a negative test:

10% of 1/25 = 0.04 = 4%

100% of 100 - 4 = 96%. So

$P(A) = 0.1*0.04 + 1*0.96 = 0.964$

Negative test and not carrying an abdornal gene:

100% of 96%. So

$P(A \cap B) = 1*0.96 = 0.96$

Compute the probability that a randomly chosen person of European ancestry does not carry an abnormal CF gene given that he /she tested negative.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.96}{0.964} = 0.9959$

0.9959 = 99.59% probability that a randomly chosen person of European ancestry does not carry an abnormal CF gene given that he /she tested negative.

8 0

3 years ago

Thirteen is at least the difference of a number v and 1

Digiron [165]

Answer: 13 ≥ v - 1

Step-by-step explanation: The equation above represents the situation; Thirteen is at least the difference of a number v and 1

4 0

3 years ago