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Vikentia [17]
3 years ago
13

What is the solution to the system of equations? ⎧⎩⎨⎪⎪x+3y−z=24x+2y+5z=13x+z=12 (−4, 1, −3) (3, 0, 3) (5, −2, −3) (−1, 2, 3)

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0
<h3>Answer:</h3>

(5, -2, -3)

<h3>Explanation:</h3>

We assume your equations are ...

  • x +3y -z = 2
  • 4x +2y +5z = 1
  • 3x +0y +z = 12

These have solution (x, y, z) = (5, -2, -3).

_____

<em>How we know</em>

Trying the choices in the last equation eliminates the first and last. Trying the second choice in the first equation eliminates it, leaving the 3rd choice as the answer you're looking for.

We also know because we can ask a graphing calculator to solve the matrix equation (or row-reduce the augmented matrix).

<em>Comment on this problem</em>

The hardest part of this problem is figuring your intent. The equations are not well-separated, so we have a hard time telling what is a constant and what is a coefficient. It took a couple of guesses to sort it out. A little editing before posting would be helpful.

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Find f(x) if it is known that f(x−6)=12x−72.
zheka24 [161]

Answer:

f(x)=12x

Step-by-step explanation

We know that f(x) is our y-coordinate and x is the x-coordinate

Next we should insert x-6 as x in the equation

This is f(x)=12(x-6)-72

But if you look at this that leads to 12x-72 (ignore y-intercept)

That is our first equation  

This means that if you take out -6 from the x

You will get f(x)=12x

(Also do you go to RSM?)

5 0
3 years ago
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BabaBlast [244]

Answer:

40%

Step-by-step explanation:

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5 0
3 years ago
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
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ddd [48]

Answer:

Length: meter

Mass: Kilogram

Volume of a solid: Cubic meter

Volume of a liquid: Liters

Temperature: Degree Celsius

Time: second

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7 0
3 years ago
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