Find the slope (rate of changes) for the table below HELPPP.

Mathematics

1 answer:

lesantik [10]3 years ago

3 0

Answer:

Its 4

Step-by-step explanation:

You would have to do the formula for finding slope

y2-y1/x2-x1

You might be interested in

U=1-3v/vt-w make t the subject<br> Answer for it

Oxana [17]

Answer:

t= - $\frac{u}{3}$ + $\frac{1}{3}$ - $\frac{w}{3}$

Step-by-step explanation:

Divide each side with variables by the one without them.

4 0

2 years ago

Cris borrowed money from her brother 6 months ago. She now owes him 56.50. She has not borrowed and she is paying 15.75 on her d

densk [106]

Answer:2.19 monthd

Step-by-step explanation:

Cris borrowed money from her brother 6 months ago. She now owes him 56.50

Let x= original money borrowed from her brother 6 months ago

She has not borrowed and she is paying 15.75 on her debt each month for the last 6 months. This means in the past 6 months,she has paid 15.75×6= 94.5

She now owes him 56.50. This means original money,x-56.50 =94.5

x = 94.5+56.50=151

If she now increases her monthly payment to 25.75, let the number of months be y, she will pay 25.75y in y months

25.75y =56.50

y =2.19 months

7 0

3 years ago

Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0

horsena [70]

Answer:

Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

Step-by-step explanation:

We need to solve the equation $x^2-8x+41=0$ using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i$