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3 years ago

D

Mathematics

1 answer:

kirza4 [7]3 years ago

8 0

Answer:

12+k/5

Quotient is a quantity produced by the division of two numbers.

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What is the area of the shaded part of the figure below?

DanielleElmas [232]

Answer:

192 i think

Step-by-step explanation:

8 0

3 years ago

HELP! PLZ I NEED THIS ASAP

harina [27]

Answer:

$2x^{4}+x^{3}-x+2$

Step-by-step explanation:

To find which one is prime, let's try to factor them all. We can use the factoring by grouping method.

$x^{3}+3x^{2}-2x-6$

$x^{3}+3x^{2}$ and $-2x-6$

$x^{2}(x+3)$ and $-2(x+3)$

So this one is not prime, since you can still factor it.

$x^{3}+2x^{2}-3x-6$

$x^{3}+2x^{2}$ and $-3x-6$

$x^{2}(x-2)$ and $3(x-2)$

So this one is not prime, since you can still factor it.

$4x^{4}+4x^{2}-2x-2$

$4x^{4}+4x^{2}$ and $-2x-2$

$4x^{3}(x+1)$ and $-2(x+1)$

So this one is not prime, since you can still factor it.

$2x^{4}+x^{3}-x+2$

$2x^{4}+x^{3}$ and $-x+2$

$x^{3}(2x+1)$ and -x+2 cannot be further factored.

Therefore, $2x^{4}+x^{3}-x+2$ is a prime.

6 0

3 years ago

15 Find the missing angle. 200 180 А A 100 B) 50 C 80 D) 70°

Korvikt [17]

Step-by-step explanation:

=> x + 80 + 20 = 180

=> x + 100 = 180

=> x = 180 - 100

=> x = 80°

6 0

3 years ago

Read 2 more answers

Given the function, d(t) = 50t, the variable t represents which of the following? Select all that apply. input output function i

34kurt

Answer:

Input

Independent variable

Step-by-step explanation:

we know that

Independent variables, are the values that can be changed or controlled in a given model or equation

Dependent variables, are the values that result from the independent variables

we have the function

$d(t)=50t$

In this problem

The function d(t) represent the dependent variable or the output

The variable t represent the independent variable or input

6 0

3 years ago

Read 2 more answers

Find the absolute maximum and absolute minimum values of f on the given interval.

anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

$f(x)=xe^{-\frac{x^{2}}{32} }$ , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

Absolute maximum is a point where the function has its greatest possible value.

Absolute minimum is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

$f(x)=xe^{-\frac{x^{2}}{32} }$

Using the product rule, first derivative will be:

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$ = 0

$1-\frac{x^{2}}{16}=0$

$\frac{x^{2}}{16}=1$

$x^{2}=16$

x = ±4

x can't be -4 because it is not in the interval [-2,8].

$f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76$

$f(4)=4e^{-\frac{4^{2}}{32} }=2.42$

$f(8)=8e^{-\frac{8^{2}}{32} }=1.08$

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0

3 years ago