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dem82 [27]
3 years ago
15

is the perpendicular bisector of . Find the value of x and the lengths of RT and ST. Show all work.

Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0
10x - 3 = 5x + 2
5x = 5
x = 1

RT = ST = 10(1) - 3 = 7

answer
x = 1
RT = 7
ST = 7
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The least common multiplier of 18 and 24 is 72. Because all of 18's multipliers do not match up with 24's multipliers until 72, it is the LCM
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Whats 2+2 i dont know what it is
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4

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2+2=4

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What is the solution set for the inequality,
creativ13 [48]

Answer:

x≤−6

Step-by-step explanation:

Let's solve your inequality step-by-step.

4(x−3)−7x≥6

Step 1: Simplify both sides of the inequality.

−3x−12≥6

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What is the other solution??
Vladimir79 [104]

Answer:

The other solution is 12.

Step-by-step explanation:

Break the solution into groups: (x^2+2x)+(-12x-24)

Factor out the x^2 from the first group to get x(x+2)

Factor out the -12 out of the second group to get -12(x-12)

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A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What
vladimir2022 [97]

Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

A(-3,1),B(1,1),C(1,-2)

we know that

The perimeter of triangle is equal to

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

A(-3,1),B(1,1)

substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

AB=4\ units

step 2

Find the distance BC

B(1,1),C(1,-2)

substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

BC=\sqrt{(-3)^{2}+(0)^{2}}

BC=3\ units

step 3

Find the distance AC

A(-3,1),C(1,-2)

substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

AC=\sqrt{(-3)^{2}+(4)^{2}}

AC=5\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=4+3+5=12\ units

6 0
3 years ago
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