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Mariulka [41]
3 years ago
6

A + B

Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

A= 0.5 and B= 4040

Step-by-step explanation:

If you write out the equation and rearrange a little it gets easier to understand.

( a + b) + (a*b) + (a - b)  you can rewrite this as

a + b + a - b + (a*b)  this is the same as 2a + ab = 2021

The way I looked at it is to figure out how to get that number 1 at the end.

The number 2020 is easy to get to.  How can you get the number 1 using either 2a or ab.

I looked at a = 0.5.   2 times 0.5 would be 1.

So now what would b have to be?  We can get the 1 at the end with the 2a part of the equation so now we have to get ab = 2020.

b = 2020/a  which using our a = 0.5, you can see that b would have to equal 4040.  Test it all out in your equation.

0.5 + 4040 + (0.5 * 4040) + 0.5 - 4040

4040.5 + (2020) - 4039.5 = 2021

So A = 0.5  and B = 4040

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Hello DestinyKiara99 o/
We can solve this equation using the quadratic formula
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x² + 6x - 24 = 0       

Δ = 6² - 4.1.(-24)
Δ = 36 + 96
Δ = 132

x = -6 +/- √132    x' = -3 + √33
<span>      --------------   /
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8 0
3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

(2x+3)=-4\pm \sqrt{5}

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2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

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3 years ago
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Stolb23 [73]
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mestny [16]

Given:

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Solution:

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Substitute x=658 to find the value of f(658).

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