2cos θ = sec θ = 1/cos θ
2cos^2 θ = 1
cos^2 θ = 1/2
cos θ = sqrt(1/2)
θ = arccos (sqrt(1/2)) = 45°
θ = 45°
3( m - 3) + 4 = 3m - 9 + 4 = 3m - 5
Answer:
-3.872983346
Step-by-step explanation:
In this case we have: cos θ = 1/4 Whose possible solutions are: θ = 2 * pi * n - Acos (1/4) θ = 2 * pi * n + Acos (1/4) Where, n belongs to the natural numbers. As sin θ <0 then the solution is: θ = 2 * pi * n - Acos (1/4) For n = 1 we get: θ = 4.965069236 radians Thus: tan θ = tan (4.965069236) = - 3.872983346 Answer: tan θ = -3.872983346
