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AfilCa [17]
3 years ago
6

Greatest common factor of 8 and 14?

Mathematics
2 answers:
Leto [7]3 years ago
8 0
The Greatest common factors is 2 because it is The common factors of 8 and 14.☺
maxonik [38]3 years ago
3 0
The greatest common factor (GCF) of 8 and 14 is 2
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Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0
3 years ago
A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.15.
mariarad [96]

Answer:

a. the probability that any one of the computers will require repair on a given day is constant

Step-by-step explanation:

The following properties must be true in order for a distribution to be binomial:

- A fixed number of trials (125 computers)

- Each trial is independent of the others (one computer requiring repair does not interfere with the likelihood of another requiring repair).

There are only two outcomes (requires repair or do not require repair)

The probability of each outcome remains constant from trial to trial (All computers have the same likelihood of requiring repair, 0.15).

Therefore, the alternative that better fits those properties is alternative a. the probability that any one of the computers will require repair on a given day is constant

8 0
4 years ago
Superman needs to save lois from the clutches of lex luthor.after flying for 6 seconds he is 1830 meter
Bond [772]

Answer:1. 2,200 meter

2.75 second

3.34 second meter

8 0
2 years ago
Use your trendline to find the temperature of your Spaghettios after 40 minutes. Is this an example of interpolation or extrapol
tamaranim1 [39]

Answer:

in 40 minutes, 15 degrees Farenheit  will be e

Step-by-step explanation:

7 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply. Log^7 1 * Log^5 25
Luda [366]

Answer:

B if you mean log_7 (1)*log_ 5 (25)

Step-by-step explanation:

I think you mean 7 and 5 as bases... like

log_7(1)*log_5(25)

log_7(1)=0 because 7^0=1

log_5(25)=2 because 5^2=25

So you have to perform the following operation 0*2=0

so 0 is definitely one answer

1  and 5*7 are definitely not equal to 0

let's look at last choice now

log_7(7)=1 because 7^1=7

so D is equivalent to saying 2*1 which is 2 not 0

so only one choice works and it is B

7 0
3 years ago
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