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Answer: Point E is located at (2, 3)</h3>
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Explanation:
The sequence PQRST has T as the last letter.
The sequence ABCDE has E as the last letter
The two letters T and E pair up or they correspond. So T will rotate to land on point E. Or T will rotate to point E's location.
Point T is at location (-3,2). So x = -3 and y = 2.
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Use the rule
(x,y) ---> (y, -x)
which is the rule we use when we rotate any point 90 degrees clockwise around the origin. We swap the x and y coordinates, then change the sign of the second coordinate (after the swap happens).
This means,
(-3, 2) ----> (2, -(-3)) = (2, 3)
or simply
(-3, 2) ---> (2, 3)
Step-by-step explanation:
Use distance formula to find the lengths of the sides.
a = √((8 − (-7))² + (-6 − (-4))²) = √229
b = √((8 − (-8))² + (-6 − (-5))²) = √257
c = √((-7 − (-8))² + (-4 − (-5))²) = √2
Use law of cosine to find one of the angles.
c² = a² + b² − 2ab cos C
(√2)² = (√229)² + (√257)² − 2(√229)(√257) cos C
2 = 229 + 257 − 2√58853 cos C
cos C = 242/√58853
C = 4.018°
To find the second angle, either use law of sines, or use law of cosine again. Using law of cosine:
b² = a² + c² − 2ac cos B
(√257)² = (√229)² + (√2)² − 2(√229)(√2) cos B
257 = 229 + 2 − 2√458 cos B
cos B = -13/√458
B = 127.405°
Finally, find the third angle using sum of angles of a triangle, or law of sines, or law of cosine. Using law of cosine:
a² = b² + c² − 2bc cos A
(√229)² = (√257)² + (√2)² − 2(√257)(√2) cos A
229 = 257 + 2 − 2√514 cos A
cos A = 15/√514
A = 48.576°
What are you referring n as
Answer:
B it maybe wrong not 100% sure
Step-by-step explanation:
I don know
