Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Answer:
<em>The answer for the first question is: </em>
<em>12/80 =</em>
<em>12 ÷ 80 =</em>
<em>0.15 =</em>
<em>0.15 × 100/100 =</em>
<em>0.15 × 100% =</em>
<em>(0.15 × 100)% =</em>
<h2><em>
15%</em></h2>
<em>Then, the answer for the second question is: </em>
<em>75% × 52 =</em>
<em>(75 ÷ 100) × 52 =</em>
<em>(75 × 52) ÷ 100 =</em>
<em>3,900 ÷ 100 =</em>
<h2><em>
39 </em></h2>
* Hopefully this helps:) Mark me the brainliest:)!!!
It is obviously C. most obviously
Answer to the question is..
32,34,36
largest is 36
8c -c= 7c
7c+6=48
7c=42
c=6
CHECK:
8(6)-(6)+6=48
48-6=42
42+6=48
48=48
