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kicyunya [14]
3 years ago
13

Write the percent as a fraction 77.5%

Mathematics
1 answer:
zysi [14]3 years ago
6 0
77.5%

Change to decimal:-

77.5 ÷ 100 = 0.775

775/1000

31/40

77.5% = 31/40
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Is -0.85 greater less than or equal to -0.98
Art [367]

Answer:

-0.85 > -0.98

or

-0.85 is greater than -0.98

Step-by-step explanation:

when comparing two number . . . you usually look first at the ones places, then if they are equal,  then you look at the tens place, then then farther back untill one number is larger than the other.

However with negive numbers, you are looking to see the smaller number (closer to zero)

so -0.85 is (smaller in a sense) but is less negetive

-0.98 is farther from zero

hope this helped. please mark me brainliest!

5 0
3 years ago
I need help with this please :)
Marina CMI [18]

9514 1404 393

Answer:

  all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

  \dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}

4 0
3 years ago
What radius of a circle is required to inscribe an equilateral triangle with an area of 35.074 in2 and an altitude of 7.794 in?
levacccp [35]

Answer:

(C) r=5.2 in

Step-by-step explanation:

firstly, we will draw diagram

we know that

centroid divides altitude into 2:1 form

so, we get

r=\frac{2}{3}\times h

now, we can plug

h=7.794

r=\frac{2}{3}\times 7.794

r=5.196in

so, option-C...............Answer

8 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
Help me and ill give you 2$ in cashapp and brainliest and 5 stars (congraz to the winner of the other thing)
Svetradugi [14.3K]

Answer:

50.020 and 50.02

Step-by-step explanation:

Hope this helps please consider making me brainliest

8 0
3 years ago
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