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Vadim26 [7]
3 years ago
15

Berkley has 10 pieces of ribbon that are 2 yards each. She uses 8 pieces that are each 3 feet long. How many feet of ribbon does

Berkley have left?
Mathematics
2 answers:
kompoz [17]3 years ago
8 0
The answer is 36. A yard is 3 feet, so you would need to do 2x3=6 then 6x10=60 then 8x3=24 then 60-24. You can check this if you feel like it, but you don't have to. Hope this can help!
allochka39001 [22]3 years ago
4 0
Well, let's convert the yards into feet. 1 yard = 3 feet. So Berkley has 10 pieces of ribbon that are each 6 feet, that's a total of 60 feet. 8 * 3 = 24, so she uses a total of 24 feet. Subtract the total amount she used from what she has: 60 - 24 = 36. Berkley has 36 feet of ribbon left.
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A pasture is twice as long as it is wide. its area is 88,200 ft2. how wide is the pasture?
OLga [1]
If the width is w and the length is l, then 2w=l. In addition, l*w=88200 (using the area formula). Plugging 2w in for l, we get 2w*w=88200=2w^2. Dividing both sides by 2, we get w^2=44100 and w=sqrt(44100)=210. 
4 0
3 years ago
URGENT! Describe step by step how to find the following equations.
yuradex [85]

Answer:

1. x = 45°

2. x = 330°

3. x = 105°

4. x = 30°

5. x = 60°

6. x = 30° or x = -45° (315°) or x = 45°

Step-by-step explanation:

1. For

cos x = sin x

∴ sin x/(cos x) = 1 = tan x

Hence, x = tan⁻¹1 = 45°

2. For

csc(x) + 3 = 1

∴ csc(x) = 1 - 3 = -2

Which gives sin x = -1/2

∴ x = sin⁻¹(-1/2) = -30° = 360 +(-30) = 330 °

3. For

cot(3x) = -1

∵ cot(3x) = 1/(tan(3x))

Hence, 1/(tan(3x)) = -1

∴ tan(3x) = -1

3·x = tan⁻¹(-1) = -45° = 360 + (-45) = 315°

Which gives, x = -45/3 = -15° or x = 105°

4. For

2·sin²(x) + 3·sin(x) = 2

We put sin(x) = y to get

2·y² + 3·y = 2 or 2·y² + 3·y - 2 =0

Factorizing gives

(2·y -1)(y+2) =0

∴ y = 1/2 or y = -2

That is, sin(x) = 1/2 or sin(x) = -2

Hence, x = sin⁻¹(1/2) = 30° or x = sin⁻¹(-2) = (-π/2 + 1.3·i)

∴ x = 30°

5. For

4cos²(x) = 3 we have;

cos²(x) = 3/4

cos(x) = √(3/4) = (√3)/2

∴ x = cos⁻¹((√3)/2) = 60°

6. For

4·sin³(x) + 1 = 2·sin²(x) + 2·sin(x)

We put sin(x) = y to get;

4·y³ + 1 = 2·y² + 2·y which gives;

4·y³ + 1 - (2·y² + 2·y) = 0 or 4·y³ -2·y² - 2·y + 1 = 0

Factorizing gives;

\frac{(2x-1)(2x+\sqrt{2}) )(2x-\sqrt{2})}{2} =0

Therefore, x = 1/2 or x = -(√2)/2 or (√2)/2

Therefore, sin(x) = 1/2 or -(√2)/2 or (√2)/2

That is x = sin⁻¹(1/2) = 30 or sin⁻¹(-(√2)/2) = -45 or sin⁻¹((√2)/2) = 45.

8 0
3 years ago
The mean weight of five complete computer stations is 163 pounds. The weights of four of the computer stations are 155 pounds, 1
Sophie [7]

Answer:

answer : 164 pounds

Step-by-step explanation:

total weight of five computers

163 x 5 = 815 pounds

the weight of the fifth one = total

weight - other four

815-155-160-165-171=164 pounds

hope it helps :)

7 0
2 years ago
Find the negation of statement <br>2+5=5​
chubhunter [2.5K]

Answer:

Can u mark brainelst plz?

Step-by-step explanation:

x − 1  >  5

x  > − 6

x  +  1  ≥  9

7 0
3 years ago
Using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $73,025?
nekit [7.7K]

The maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month, so the correct option is A.

<h2><u>How to determine the amount using the standard 28/36 guides?</u></h2>

To determine, using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $73,025, the following calculation must be made:

  • ((73025 x 36) / 100) / 12 = X
  • (2,628,900 / 100) / 12 = X
  • 26,289 / 12 = X
  • 2,190.75 = X

Therefore, the maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month.

Learn more about mortgages in brainly.com/question/20589209

4 0
2 years ago
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