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Sphinxa [80]
3 years ago
11

What is the answer for -77=7b

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

b= -11

Step-by-step explanation:

-77=7b

÷7. ÷7

-11=b

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Haynes High School chartered buses for 60 students to go on a field trip. Valley High School chartered buses for 80 students.
Svetradugi [14.3K]

Answer: $20

Step-by-step explanation:

Let 'x' be the cost of a ticket at Haynes

Let 'y' be the cost of a ticket at Valley

Since the total cost from both schools are the same, we can write it as:

60x=80y

Since the cost of tickets at Valley was $5 less than Haynes, we can write it as:

y=x-5

Now we have two equations, we can use to substitute into the other expression:

60x=80y

60x=80(x-5) we substitute y in this equation with the other equation

60x=80x-400

-20x =-400

x = 20

Therefore the cost of the ticket at Haynes is $20 and the cost of the ticket at Valley is $15.

5 0
2 years ago
How do you write 3 2/4 as a fraction greater t hff an 1
elena55 [62]

Answer:


Step-by-step explanation:

Hope this helps  3 over 4 hope this helps

3 0
3 years ago
What is twenty times negative fifteen
xeze [42]

Answer:

  • \boxed{20\times-15=-300}

Step-by-step explanation:

5 0
3 years ago
Geometric of <br> 1/3, 2/9, 4/27, 8/81, 16/243
Nataliya [291]
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5 0
3 years ago
Help math question derivative!
atroni [7]
Let f(x)=\sec^{-1}x. Then \sec f(x)=x, and differentiating both sides with respect to x gives

(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1
f'(x)=\dfrac1{\sec f(x)\tan f(x)}

Now, when x=\sqrt2, you get

(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}

You have \sec^{-1}\sqrt2=\dfrac\pi4, so \sec\left(\sec^{-1}\sqrt2\right)=\sqrt2 and \tan\left(\sec^{-1}\sqrt2\right)=1. So (\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}
5 0
4 years ago
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