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3 years ago

What is the trig. ratio for the tangent of angle C? Be sure to simply your fraction to simplest form.

Mathematics

1 answer:

I am Lyosha [343]3 years ago

5 0

$\\ \sf\longmapsto tan\Theta=\dfrac{Perpendicular}{Base}$

$\\ \sf\longmapsto tanC=\dfrac{AB}{AC}$

$\\ \sf\longmapsto tanC=\dfrac{48}{64}$

$\\ \sf\longmapsto tanC=\dfrac{3}{4}$

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Circle 1: center (8, 5) and radius 6

PolarNik [594]

We have that
Circle 1: center (8, 5) and radius 6
Circle 2: center (−2, 1) and radius 2

we know that
the equation of a circle is
(x-h)²+(y-k)²=r²
for the circle 1---------> (x-8)²+(y-5)²=36
for the circle 2---------> (x+2)²+(y-1)²=4

using a graph tool
see the attached figure

Part A)What transformations can be applied to Circle 1 to prove that the circles are similar?

we know that
r1/r2---------> 6/2------> 3

to prove that the circle 1 and circle 2 are similar, the radius of circle 1 must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down

the answer part A) is
the radius of circle 1 must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down

Part B) What scale factor does the dilation from Circle 1 to Circle 2 have?

the answer Part B) is
the scale factor is (3/1)

6 0

3 years ago

Simplify the cubed root of six over the fourth root of six

Ipatiy [6.2K]

Answer:

six raised to the one twelfth power

Step-by-step explanation:

The cubed root of 6/the fourth root of 6 equals (6^1/3)/(6^1/4)

6^((1/3)-(1/4))

6^((4-3)/12)

6^1/12

8 0

3 years ago

Read 2 more answers

There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s

harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

Original Mean = $70,000

$\frac{\sum X}{n}$ = $70,000 ⇒ $\sum X$ = 70,000 * 10 = $700,000

New $\sum X$ after change = $700,000 - $100,000 + $1,000,000 = $1600000

Therefore, New mean = $\frac{1600000}{10}$ = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = $20000^{2}$ i.e. $20000^{2}$ = $\frac{\sum x^{2} - n*xbar }{n -1}$

Original $\sum x^{2}$ = ( $20000^{2}$ * (10-1)) + (10 * 70,000) = $3,600,700,000

New $\sum x^{2}$ = $3,600,700,000 - $100,000^{2} + 1,000,000^{2}$ = 9.936007 * $10^{11}$

New Variance = $\frac{new\sum x^{2} - n*new xbar }{n -1}$ = $\frac{9.936007 *10^{11} - 10*160000 }{10 -1}$ = 1.103999 * $10^{11}$ Therefore, standard deviation after change = $\sqrt{1.103999 * 10^{11} }$ = $332264.804 .