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ddd [48]
3 years ago
9

Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form.

Mathematics
1 answer:
3241004551 [841]3 years ago
3 0
(3,4)(2,-1)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (-1-4) / (2 - 3) = -5/-1 = 5

y = mx + b
slope(m) = 5
u can use either of ur points...(3,4)...x = 3 and y = 4
now we sub and find b, the y int
4 = 5(3) + b
4 = 15 + b
4 - 15 = b
- 11 = b

so ur equation is : y = 5x - 11 <===

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wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

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Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

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\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

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Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

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