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guapka [62]
3 years ago
9

Sammy and kaden went fishing using live shrimp as bait. Sammy brought 8 more shrimp than kaden brought. When they combined their

shrimp they had 32 shrimp altogether. How many shrimp did each boy bring
Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer: kaeden brough 12 sammy brought 20

Step-by-step explanation:

i know that 16+16=32 and

15+17=32 and

14+18=32 and

13+19= 32 and

12+20=32. it’s gonna be 12 and 20 because those numbers add up to 32 and are 8 away from each other. since sammy had more fish he brought 20 and kaeden brough 12.

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Find the surface area of a hexagonal prism if the length of each side of the hexagonal base is 4 cm and the height is 7 cm.
olya-2409 [2.1K]

The surface area of a hexagonal prism willl be 251.13844 cm².

<h3>What is the surface area?</h3>

The total land area of all the faces of a three-dimensional object is its surface area. When we wish to wrap something in real life, we employ the notion of surface areas of distinct things.

A=6ah+3√3a²

A=6×4×7+3√3×4²

A≈251.13844

Hence the surface area of a hexagonal prism willl be 251.13844 cm².

To learn more about the surface area, refer to the link;

brainly.com/question/2835293

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3 0
2 years ago
Type the correct answer for each.
xxTIMURxx [149]
If point \left(x,\ \frac{\sqrt{7}}{3}\right) is on the unit ircle, then:

x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\  \\ \Rightarrow x^2+ \frac{7}{9} =1 \\  \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9}  \\  \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}

Since, the point is in the second quadrant, x is negative.

Thus, (x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)

Part A:

3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\  \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\  \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\  \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta

Therefore, -6\tan\theta=3\sqrt{7}.



Part B:

- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} }  \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x}  \\  \\ =\tan\theta

Therefore, \tan\theta=- \frac{ \sqrt{7} }{2}
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