Answer:
Step-by-step explanation:
Prime numbers have only one factor pair, the number itself and 1. Some polynomials can be factored and some cannot be so a polynomial is a prime polynomial if it can't be factored into the standard linear form of (x+a)((x+b).
For the given polynomial x^3+3x^2+2x+6
Re-arranging the Polynomial to find out whether it could be factored or not
x^3+2x+3x^2+6=0
x(x^2+2) +3 (x^2+2)=0
(x+3)(x^2+2)=0
x+3=0 and x^2+2=0
x=-3, x^2= -2
x=-3, x=sqrt(-2), x= -sqrt(-2)
As the polynomial is factorable it is not prime
14 multiplied by 14 equals 196 which is closer to 14.0 than to 14.5
Hope this helps please lmk if I was right or wrong
Answer:
all you need to do is multiply all of the numbers together.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Simplifying
2x + 13 = 0
Reorder the terms:
13 + 2x = 0
Solving
13 + 2x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-13' to each side of the equation.
13 + -13 + 2x = 0 + -13
Combine like terms: 13 + -13 = 0
0 + 2x = 0 + -13
2x = 0 + -13
Combine like terms: 0 + -13 = -13
2x = -13
Divide each side by '2'.
x = -6.5
Simplifying
x = -6.5