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3 years ago

Someone pls help I really don’t get it

Mathematics

1 answer:

poizon [28]3 years ago

6 0

So the probability that the next person is costa Rican means 1 is added to the numerator and denominator. this can then be simplified to
3/10

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just as a piece of wood that is 8 foot long he needs to cut pieces that are seven eighths of a foot long how many pieces will he

BlackZzzverrR [31]

He would make 7 peices

7 0

3 years ago

A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR? pythagorus theorem

algol13

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

h²=p²+b²

80²=QR²+60²

QR²=80²-60²

QR= $\sqrt{2800}$

QR=20 $\sqrt{7}$ =52.9=53cm

QR=53cm.

5 0

3 years ago

Help please :) ..................

brilliants [131]

Answer:

1587.6 m²

Step-by-step explanation:

$A=\frac{1}{2} bh$ where b is the base length and h is the height (b and h on the triangle will always be perpendicular to each other)

Plug in 75.6 m as b and 42 m as h

$A=\frac{1}{2} (75.6)(42)\\A=\frac{1}{2}( 3175.2)\\A=1587.6$

I hope this helps!

3 0

2 years ago

A candy bar box is in the shape of a triangular prism. The volume of the box is 3,240 cubic centimeters.

SashulF [63]

B: To make the box, we need 2 triangular ends,

and 3 rectangular sides. Side the volume = 3240

and the height = 30, the area of each base (end) = 108.

The sides have areas of 30 x 42 = 720, and 30 x 15 = 450,

and there are 2 of those. So total area = 108 + 108 + 720 + 900 = 1836 cm^2

creds to yahoo answer

8 0

2 years ago

In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°

7 0

3 years ago

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