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riadik2000 [5.3K]
3 years ago
15

Someone pls help I really don’t get it

Mathematics
1 answer:
poizon [28]3 years ago
6 0
So the probability that the next person is costa Rican means 1 is added to the numerator and denominator. this can then be simplified to
3/10

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Self-Check<br> Practice Exercise 4
ryzh [129]

Answer:

A= Congruent

B= Supplementary

C= Congruent

D= Congruent

E=Supplementary

Step-by-step explanation:

5 0
3 years ago
NEED HELP.
kirza4 [7]

Answer:

For instance, if the point (1, 3) is on the graph of the function, then the point (3, 1) is on the graph of the inverse. That is, if you start with x = 1, you will go to y = 3; then you plug this into the inverse, and you'll go right back to x = 1, where you started from.

5 0
3 years ago
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Simplify. (-4x^4+x^2-4)+(5x^2-4)(−4x ​4 ​​ +x ​2 ​​ −4)+(5x ​2 ​​ −4)
zloy xaker [14]
-4x^4 - 15x^2 + 1 - 19/x^2 is your answer

Hope I helped :)
8 0
3 years ago
Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0
erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

15x^2-kx+1=0           (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0
3 years ago
Write an equation in standard form of the line that passes through the given point and has the given slope. (5,0) m=4/3
sveticcg [70]

\text{The standard form of a line:}\ Ax+By=C

\text{The point-slope form:}

y-y_1=m(x-x_1)

\text{We have the point (5, 0) and the slope}\ m=\dfrac{4}{3}

\text{substitute:}\\\\y-0=\dfrac{4}{3}(x-5)\qquad|\text{use distributive property}\\\\y=\dfrac{4}{3}x-\dfrac{20}{3}\qquad|\text{multiply both sides by 3}\\\\3y=4x-20\qquad|\text{subtract 4x from both sides}\\\\-4x+3y=-20\qquad|\text{change the signs}\\\\\boxed{4x-3y=20}

4 0
3 years ago
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