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Vadim26 [7]
3 years ago
13

Solve −4x3 (2x2 −9x2 ) =

Mathematics
2 answers:
Korolek [52]3 years ago
6 0

Answer:

+168

Step-by-step explanation:

In the attached file

Tamiku [17]3 years ago
4 0

Answer:

the answer is 28x ^ 5

Step-by-step explanation:

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If c(x)=4x-2 and d(x)=x^2+5 , what is (c o d) (x)
Nookie1986 [14]

Answer:

4x² + 18

Step-by-step explanation:

note that (c ○ d )(x) = c(d(x))

To evaluate substitute x = d(x) into c(x), that is

c(d(x))

= c(x² + 5)

= 4(x² + 5) - 2

= 4x² + 20 - 2

= 4x² + 18

3 0
3 years ago
Plssss helppppp!!!!!!!!!
Ira Lisetskai [31]

Answer:

it is two because one apple plus one apple equals two

it is 2

8 0
3 years ago
Read 2 more answers
A. [4 marks]
storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is u_{n}=u_{1}+(n-1)d , where

  • u_{1} is the first term
  • d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is u_{n}=u_{1}r^{n-1} , where

  • u_{1} is the first term
  • r is the common ratio between each two consecutive terms r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∵ u_{1} of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ u_{2} , u_{3} , u_{6} are the first 3 terms of a geometric sequence

∵ u_{2} = 1 + (2 - 1)d

∴ u_{2} = 1 + d

∵ u_{3} = 1 + (3 - 1)d

∴ u_{2} = 1 + 2d

∵ u_{6} = 1 + (6 - 1)d

∴ u_{2} = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

   (1 + 5d)

∵ The common ratio in the geometric sequence is r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∴ r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

- Use cross multiplication with the equal fractions

∵ \frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0
3 years ago
NEED ANSWERS ASAP, 100 POINTS! There are twenty classes at each of two middle schools. The number of students in each class at e
DiKsa [7]

Note: You missed to add the dot plots chart. As I found the chart after a little research. Thus, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.

Answer:

'There are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

Step-by-step explanation:

From the diagram, it is clear that

The data set containing Poplar Middle School:

20   20   20   21   21   21   21   21   22   22   22   22   22   22   22   23   23   23   23   24  

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

\mu = 435/20

  =\frac{87}{4}

   = 21.75

The data set containing Oak Middle School:

20   21   21   22   22   23   23   23   23   24   24   24   25   25   26   26   27   27   28   29  

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

\mu = 483/20

   =24.15

So, the difference in mean will be:

                                            24.15 - 21.75 = 2.4

Therefore, 'there are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

5 0
3 years ago
HELP ME PLEASE I BEG YOU
spayn [35]

Answer:

∠ K = 35° and ∠ L = 105°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

let ∠ K = x then ∠ L = 3x

Sum the angles and equate to 180

3x + x + 40 = 180, that is

4x + 40 = 180 ( subtract 40 from both sides )

4x = 140 ( divide both sides by 4 )

x = 35

Thus

∠ K = 35° and ∠ K = 3x = 3 × 35 = 105°

5 0
3 years ago
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