Question

A line parallel to y=3/5x-3 and passing through the point (15,-2)

Answer 1

Answer:

y = $\frac{3}{5}$ x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{3}{5}$ x - 3 ← is in slope- intercept form

with slope m = $\frac{3}{5}$

Parallel lines have equal slopes, thus

y = $\frac{3}{5}$ x + c ← is the partial equation of the parallel line

To find c substitute (15, - 2) into the partial equation

- 2 = 9 + c ⇒ c = - 2 - 9 = - 11

y = $\frac{3}{5}$ x - 11 ← equation of parallel line

Answer 2

$\huge\boxed{y+2=\frac{3}{5}(x-15)}$

We will use point-slope form, where $m$ is the slope and $(x_1,y_1)$ is a known point on the line.

$y-y_1=m(x-x_1)$

First, find the slope. Since the two lines will be parallel, they'll share the same slope of $\frac{3}{5}$.

$y-y_1=\frac{3}{5}(x-x_1)$

Substitute in the known point.

$y-(-2)=\frac{3}{5}(x-15)$

Simplify the negative subtraction.

$\large\boxed{y+2=\frac{3}{5}(x-15)}$

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