On the number line above, PQ= 3/4 , PS= 8 1/12 , and RS= 2 1/2 . What is the position of point R ?

Mathematics

1 answer:

sergiy2304 [10]3 years ago

6 0

Answer:

how do you know what the answer is

Step-by-step explanation:

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PLEASE HELP WITH ALGEBRA

ratelena [41]

y - y₁ = m(x - x₁)
y - (-7) = -1¹/₅(x - (-3))
y + 7 = -1¹/₅(x + 3)
y + 7 = -1¹/₅(x) - 1¹/₅(3)
y + 7 = -1¹/₅x - 3³/₅

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-17 - (-2)}{3 - (-9)} = \frac{-17 + 2}{3 + 9}} = \frac{-15}{12} = \frac{-5}{4} = -1\frac{1}{4}$

y - y₁ = m(x - x₁)
y - (-2) = -1¹/₄(x - (-9))
y + 2 = -1¹/₄(x + 9)
y + 2 = -1¹/₄(x) - 1¹/₄(9)
y + 2 = -1¹/₄x - 11¹/₄
- 2 - 2
y = -1¹/₄x - 13¹/₄

y - y₁ = m(x - x₁)
y - (-3) = ⁻¹/₄(x - 8)
y + 3 = ⁻¹/₄(x) + ¹/₄(8)
y + 3 = ⁻¹/₄x + 2
- 3 - 3
y = ⁻¹/₄x - 1

y - y₁ = m(x - x₁)
y - (-17) = ¹/₂(x - (-6))
y + 17 = ¹/₂(x + 6)
y + 17 = ¹/₂(x) + ¹/₂(6)
y + 17 = ¹/₂x + 3
- 17 - 17
y = ¹/₂x - 14

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-4 - 8}{-4 - 6} = \frac{-12}{-10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$

y - y₁ = m(x - x₁)
y - 8 = 1¹/₅(x - 6)
y - 8 = 1¹/₅(x) - 1¹/₅(6)
y - 8 = 1¹/₅x - 7¹/₅
+ 8 + 8
y = 1¹/₅x + ⁴/₅

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4 years ago