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dexar [7]
2 years ago
8

Explain why x squared = 16 has two solutions. What are the solutions.

Mathematics
1 answer:
BabaBlast [244]2 years ago
3 0
A negative number * another negative number gives a positive value

A positive number * another positive number also gives a positive value

The solutions are -4, 4


Hope this helps :)
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NEED The FULL equation. Will give Brainly. Thank you!
Ghella [55]

Answer:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

Step-by-step explanation:

we are given a function

\displaystyle \sf h(x) =  \frac{2x - 6}{4 {x}^{2}  + 8}

we would like to simplify it for h(-1)

in order to do so

substitute the value of x

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { (- 1)}^{2}  + 8}

by order of PEMDAS

simplify square:

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { ( 1)}^{}  + 8}

simplify multiplication:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{4 { }^{}  + 8}

simplify addition:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{12}

simplify subtraction:

\displaystyle \sf h( - 1) =  \frac{   - 8}{12}

reduce fraction:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

5 0
3 years ago
PLease help me i will give brainliest
Feliz [49]
B is correct the devotion is only 2 compared to 4.

A is wrong because variate A has higher trees then variate B
C is wrong because deviation for A is 4 compared to 2 ( opposite of B)
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What is the type of sweet wine made in tuscany using dried grapes and extensive aging?
Sveta_85 [38]
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2 years ago
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sattari [20]

Answer: The interest is: $150.00

The formula we'll use for this is the simple interest formula, or:

Where:

   P is the principal amount, $6000.00.

   r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.

   t is the time involved, 6....month(s) time periods.

   Since your interest rate is "per year" and you gave your time interval in "month(s)" we need to convert your time interval into "year" as well.

       Do this by dividing your time, 6- month(s), by 12, since there's 12 months in 1 year.

   So, t is 0.5....year time periods.

To find the simple interest, we multiply 6000 × 0.05 × 0.5 to get that:

The interest is: $150.00

8 0
3 years ago
Represent the following expressions as a power of the number a (a +0)<br> a^2 * (a^0)^3/a^11
LekaFEV [45]
I have no idea how to do this problem i dont know what a is
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