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scoundrel [369]
3 years ago
5

Does this graph represent a function?

Mathematics
2 answers:
o-na [289]3 years ago
4 0
The answer is A because is dose pass the vertical line test
igomit [66]3 years ago
4 0

Answer:

A. Because it pass the vertical line test.

Step-by-step explanation:

Let us first understand the Vertical Line test. In this test , we draw few random vertical lines on graph and check whether any one or more than one line intersect the graph, no matter once or more. If there exists a line which intersects the graph , we say graph passes the vertical line test.

Hence this graph passes vertical line test because there are many vertical lines which intersect it.

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What is the absolute value of |-15|? Explain!
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The coach bought a hamburger and a $1.75 drink for the 10 members of the team. He spent a total of $36.00. Write and nu solve an
Angelina_Jolie [31]

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1.85

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3 years ago
A concession stand at a sports stadium sells 600 bags of peanuts (each game) if the price of each bag is $4.00. For each $0.25 i
grin007 [14]

Answer:

Price = $4.50

Maximum revenue = $2,430

Step-by-step explanation:

The concession stand sells 600 bags of peanut at $4.00 (600, $4.00).

If there is a $1 increase in price, the number of bags old will decrease by 120, which mens that 480 bags of peanuts will be sold at $5.00 (480, $5.00).

Tracing a linear relationship between price and quantity sold with the two given points:

m = \frac{5-4}{480-600}\\ m=-\frac{1}{120}

P - P_0=m*(Q-Q_0)\\P-4.00=-\frac{1}{120} (Q-600)\\P= -\frac{1}{120}Q +9

The revenue function is given by the price multiplied by the quantity sold:

R=Q*P= (-\frac{1}{120}Q +9)*Q\\R=-\frac{1}{120}Q^2 +9Q

The value of 'Q' for which the derivate of the revenue function is zero, is the output level for which revenue is maximum:

R'=0=-\frac{2}{120}Q+9\\Q_{max} = 540\\P_{max} = -\frac{540}{120} +9\\P_{max} =\$4.50

The total revenue of 540 units at $4.50 per unit is:

R = \$4.50*540\\R=\$2,430

6 0
3 years ago
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