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Burka [1]
2 years ago
15

There are 363 students at Meadowbrook High School. There are 10 more

Mathematics
1 answer:
saveliy_v [14]2 years ago
4 0
First, put each grade in terms of x. Most grades are compared to Sophomores, so I made that x

Freshmen = x + 10
Sophomores = x
Juniors = x + 20
Seniors = (x + 10) + 7 = x + 17

Then, the total number of students = 363, so we’ll make an equation that adds them all up in terms of x to equal 363

(x + 10) + x + (x + 20) + (x + 17) = 363

Combine like terms:
4x + 47 = 363
Subtract 47 from both sides:
4x = 316
Divide both sides by 4:
x = 79

The question was how many seniors there are. Seniors were x + 17, so 79 + 17 = 96
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How many minutes are there in 4 hours,30 minutes please help I will give you 12 points
Inessa [10]
There are 60 minutes in one hour. If we are trying to find how many minutes are in 4 hours and 30 minutes, we first need to find out how many minutes are in 4 hours.
To do that, we just need to multiply the amount of minutes in an hour by the amount of hours we have.

60 * 4 = 240

Then, we just add the remaining 30 minutes.

240 + 30 = 270

There are 270 minutes in 4 hours and 30 minutes.
Hope that helped! =)
3 0
3 years ago
Read 2 more answers
A triangle has a base of 6 yards and a height of 9 yards. By how much does the height need to decrease for the area to decrease
ELEN [110]
3.5 yards


Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
3 0
2 years ago
A small class has 10 students, 4 of whom are girls and 6 of whom are boys. The teacher is going to choose two of the students at
Vinil7 [7]

Answer:

1/3

Step-by-step explanation:

Dividing the amount of boys (6) by the amount of students (10), and then reiterating that, subtracting 1 from both, you get:
(6/10) x (5/9) which equals a third.

7 0
2 years ago
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
All it's asking is to solve, I've tried to drop the exponent down but I get stuck
Deffense [45]
X^6= 3^12
(X^6) ^1/6. = (3^12)^1/6
X=9
6 0
3 years ago
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