UDP = connectionless vs. TCP is connection oriented.
Answer:
The answer to this question is given below in the explanation section. the correct option is C.
Explanation:
This is Java code statement:
System.out.print("Computing\nisInfun");
The output of this code statement is
Computing
isInfun
However, it is noted that the C option is not written correctly, but it is guessed that it will match to option C.
This Java code statement first prints "Computing" and then on the next line it will print "isInfun" because after the word "Computing" there is a line terminator i.e. \n. when \n will appear, the compiler prints the remaining text in the statement on the next line.
Answer:
20 will be displayed on the console.
Explanation:
Given code is:
var numList = [10,20,30];
console.log(numList[numlist.length-2]);
The first line of code declares an array named numList and assigns it values given in the square brackets.
The second line of code is written to display the element on the index obtained by [numlist.length-2]
[numlist.length-2] means the second index.
Hence,
after running the code on JavaScript editor and dry running the code
20 will be displayed on the console.
import java.util.Scanner;
public class MyClass1 {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
int smallest = 0, largest = 0, num, count = 0;
while (true){
System.out.println("Enter a number (-1 to quit): ");
num = scan.nextInt();
if (num == -1){
System.exit(0);
}
else if (num < 0){
System.out.println("Please enter a positive number!");
}
else{
if (num > largest){
largest = num;
}
if (num < smallest || count == 0){
smallest = num;
count++;
}
System.out.println("Smallest # so far: "+smallest);
System.out.println("Largest # so far: "+largest);
}
}
}
}
I hope this helps! If you have any other questions, I'll do my best to answer them.