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Veronika [31]
3 years ago
13

While troubleshooting a network connection problem for a coworker, you discover the computer is querying a nonexistent DNS serve

r. What command line utility can you use to assign the correct DNS server IP address?
Computers and Technology
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

nslookup ifconfig.

Explanation:

The nslookup is used a number of times by network admins to troubleshoot DNS related problems. In addition, this command finds IP addresses and name servers of hosts. This utility command queries the DNS database tables from every host in a network. It then determines the host name and issues an IP. It sort of converts your domain name into an IP addresses. This command combined with ifconfig finds the correct DNS servers and assigns the correct DNS server IP.

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a. displays the sum of all even numbers between 2 and 100 (inclusive). b. displays the sum of all squares between 1 and 100 (inc
LuckyWell [14K]

Answer:

The program required is in the explanation segment.

Explanation:

Program :

import math

# a. displays the sum of all even numbers between 2 and 100 (inclusive).

print("All even numbers from 2 to 100 inclusive ")

sum=0

i=2

while i<=100:

if i %2 ==0:

sum=sum+i

print(i,end=" ")

i=i+1

print("\nThe sum of all even numbers between 2 and 100 (inclusive) :",sum);

#b. displays the sum of all squares between 1 and 100 (inclusive).

print("\nAll squares numbers from 1 to 100 inclusive:")

i=1

sum=0

while i<=100:

print(i*i,end=" ")

i=i+1

sum=sum+(i*i)

print("\n\nThe sum of all squares between 1 and 100 (inclusive) is :",sum)

#c. displays the powers of 2 from 1 up to 256.

print("\nAll powers of 2 from 2 ** 0 to 2 ** 8:")

i=0

while True:

p=math.pow(2,i)

if p>256:

break

print("2 ** ",i," is ",int(p))

i=i+1

#d. displays the sum of all odd numbers between a and b (inclusive), where a and b are inputs

print("\nCompute the sum of all odd integers between two intgers ")

a=int(input("Enter an integer:"))

b=int(input("Enter another integer: "))

count = 0

temp=a

sum=0

while a<=b:

if a%2!=0:

print(a,end=" ")

sum=sum+a

a=a+1

print("\nThe total of the odd numbers from ", temp ," to ", b ,"is",sum)

#e.displays the sum of all odd digits of an input. (For example, if the input is 32677, the sum would be 3 + 7 + 7 = 17.)

print("\nCompute the sum of the odd digits in an integer ")

n=int(input("Enter an integer:"))

count=0

sum=0

temp=n

while n!=0:

rem = n%10

if rem%2!=0:

sum=sum+rem

count=count+1

n=int(n/10)

print("Sum of the odd digits is ",sum)

print("The total of the odd digits in ",temp," is ",count)

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3 years ago
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