In general, a maximum of 25% to 30% of one's gross income can be spent on rent. So, according to this lets find out the values.
Given is,
The gross annual salary of Kathleen = $56820
So, her monthly income becomes = ![\frac{56820}{12}= 4735](https://tex.z-dn.net/?f=%5Cfrac%7B56820%7D%7B12%7D%3D%204735)
So, its 25% is =
= 1183.75
And 30% becomes =
= 1420.50
If we take an average of both, as the value will lie between these two figures we get, (1183.75+1420.50)/2 = $1302.12
Hence, this value lies close to $1326. So, the answer will be option B - $1326
We have the equation:
![x^2+3x=40](https://tex.z-dn.net/?f=x%5E2%2B3x%3D40)
We have to find its roots with the quadratic formula:
![\begin{gathered} x^2+3x-40=0 \\ x=\frac{-3}{2\cdot1}\pm\frac{\sqrt[]{3^2-4\cdot1\cdot(-40)}}{2\cdot1} \\ x=-\frac{3}{2}\pm\frac{\sqrt[]{9+160}}{2} \\ x=-\frac{3}{2}\pm\frac{\sqrt[]{169}}{2} \\ x=-\frac{3}{2}\pm\frac{13}{2} \\ x_1=-\frac{3}{2}-\frac{13}{2}=-\frac{16}{2}=-8 \\ x_2=-\frac{3}{2}+\frac{13}{2}=\frac{10}{2}=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2%2B3x-40%3D0%20%5C%5C%20x%3D%5Cfrac%7B-3%7D%7B2%5Ccdot1%7D%5Cpm%5Cfrac%7B%5Csqrt%5B%5D%7B3%5E2-4%5Ccdot1%5Ccdot%28-40%29%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20x%3D-%5Cfrac%7B3%7D%7B2%7D%5Cpm%5Cfrac%7B%5Csqrt%5B%5D%7B9%2B160%7D%7D%7B2%7D%20%5C%5C%20x%3D-%5Cfrac%7B3%7D%7B2%7D%5Cpm%5Cfrac%7B%5Csqrt%5B%5D%7B169%7D%7D%7B2%7D%20%5C%5C%20x%3D-%5Cfrac%7B3%7D%7B2%7D%5Cpm%5Cfrac%7B13%7D%7B2%7D%20%5C%5C%20x_1%3D-%5Cfrac%7B3%7D%7B2%7D-%5Cfrac%7B13%7D%7B2%7D%3D-%5Cfrac%7B16%7D%7B2%7D%3D-8%20%5C%5C%20x_2%3D-%5Cfrac%7B3%7D%7B2%7D%2B%5Cfrac%7B13%7D%7B2%7D%3D%5Cfrac%7B10%7D%7B2%7D%3D5%20%5Cend%7Bgathered%7D)
Answer:
The roots (or solutions) of the equation are:
x1 = -8
x2 = 5
Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction. Therefore, 1 1/6 is the quotient of the division problem (2/3) / (4/7).