Question

I need help finding x using the pythagorean theorem.

Answer 1

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{68}\\ a=\stackrel{adjacent}{60}\\ b=\stackrel{opposite}{x}\\ \end{cases} \\\\\\ \sqrt{68^2-60}=x\implies \sqrt{4564}=x\implies 67.55738\approx x$

Answer 2

The value of x =32 I’m sure