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3 years ago

Which value below is included in the solution set for the inequality statement?

Mathematics

1 answer:

mixas84 [53]3 years ago

7 0

You haven't provided any value, but I can tell you the solution set for the inequality.

First of all, expand both sides:

$-3x+12 > 6x-6$

Add 3x to both sides:

$12 > 9x-6$

Add 6 to both sides:

$18 > 9x$

Which is of course equivalent to

$9x < 18$

Divide both sides by 9

$x < 2$

So, every number smaller than 2 is part of the solution of this inequality.

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Enter the common ratio for the geometric sequence below.

Sav [38]

Answer:

r = $\frac{3}{2}$

Step-by-step explanation:

The common ratio (r) in a geometric sequence is any term divided by the previous term, that is

r = $\frac{6}{4}$ = $\frac{9}{6}$ = $\frac{3}{2}$

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4 years ago

For what values of b are the vectors \langle -46, b, 10 \rangle and \langle b, b^2, b \rangle orthogonal

Jet001 [13]

Answer:

b = 6 or b = -6 (non-zero vectors)

b = 0 (zero vector)

Step-by-step explanation:

Two vectors $\vec{a}=\langle a_1,a_2,a_3\rangle$ and $\vec{b}=\langle b_1,b_2,b_3\rangle$ are orthogonal if their dot product is equal to 0, or in other words

$a_1\cdot b_1+a_2\cdot b_2+a_3\cdot b_3=0$

In your case,

$\vec{a}=\langle -46, b, 10\rangle\\ \\\vec{b}=\langle b,b^2,b\rangle$

Hence, if vectors a and b are orthogonal, then

$-46\cdot b+b\cdot b^2+10\cdot b=0\\ \\-46b+b^3+10b=0\\ \\b^3-36b=0\\ \\b(b^2-36)=0\\ \\b(b-6)(b+6)=0\\ \\b=0\text{ or }b=6\text{ or }b=-6$

Note, then if b = 0, then $\vec{b}=\langle 0,0,0\rangle$ and zero-vector is orthogonal to any other vectors.

Thus, b = 6 or b = -6.

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3 years ago

A resort hotel offers two weekend specials.

katen-ka-za [31]

Answer:

$44 per 1 meal

Step-by-step explanation:

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3 years ago

Given: 9x > -36. Choose the solution set. {x | x < -4} {x | x < 4} {x | x > 4} {x | x > -4}

olchik [2.2K]

$\bf{9x > -36 }$

Divide both sides by 9.

$\bf{\dfrac{9x}{9} > \dfrac{-36}{9} }$

$\bf{x > -4 \ \ \to \ \ \ Answer}$

<h2>{ Pisces04 }</h2>

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2 years ago

Read 2 more answers

On your own sheet of grid paper, draw an irregular figure which has an area of approximately 12 square units.

harina [27]

1 row of 2 squares, 1 row of 4 squares, 1 row of 6 squares. Hope this helps!

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3 years ago