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2 years ago

Which value below is included in the solution set for the inequality statement?

Mathematics

1 answer:

mixas84 [53]2 years ago

7 0

You haven't provided any value, but I can tell you the solution set for the inequality.

First of all, expand both sides:

$-3x+12 > 6x-6$

Add 3x to both sides:

$12 > 9x-6$

Add 6 to both sides:

$18 > 9x$

Which is of course equivalent to

$9x < 18$

Divide both sides by 9

$x < 2$

So, every number smaller than 2 is part of the solution of this inequality.

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3 years ago

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3 years ago

X+9=2x-3 FIND THE X!!!!!!

Ierofanga [76]

Answer:

x = 12

Step-by-step explanation:

To find "x", we need to isolate it. This means move "x" to the left side, and everything else to the right side.

When moving a number, do its reverse operation to the entire equation.

x + 9 = 2x - 3

x - 2x + 9 = 2x - 2x - 3 Subtract 2x from both sides

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-x + 9 - 9 = -3 - 9 Subtract 9 from both sides

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-x/-1 = -12/-1 Divide both sides by -1 to get rid of the negatives

x = 12 Final answer

Check your answer. Split the equation for the left and right sides. Substitute "x" for the answer "12".

LS: (left side)

x + 9

= 12 + 9 Add

= 21

RS: (right side)

2x - 3

= 2(12) - 3 Multiply before subtracting

= 24 - 3 Subtract

= 21

Both sides equal to 21 when "x" is 12.

LS = RS left side equals right side

Therefore the answer is correct.

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3 years ago

2. Is the data set "dollars of sales per week” quantitative or qualitative?

Ipatiy [6.2K]

Answer:

this would be quantitative.

Step-by-step explanation:

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3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

3 years ago

Read 2 more answers