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tester [92]
2 years ago
12

At give rates how far would each horse run in 12 minutes

Mathematics
1 answer:
Gemiola [76]2 years ago
3 0
What are the given rates??
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Last month you spent $20 on clothing. This month you spent 180% of what you spent last month. How much did you spend this month?
frutty [35]
Stan Han Jisung!!!!!He literally cute!!hdbdbdkkdjd

8 0
2 years ago
You buy items costing $1900 and finance the cost with a fixed installment loan for 24 months at 8% simple interest per year.
ddd [48]

9514 1404 393

Answer:

  1. $304
  2. $91.83

Step-by-step explanation:

1. The finance charge is found from the simple interest formula;

  I = Prt

where P is the principal amount, r is the annual rate, and t is the number of years.

24 months is 2 years, so the interest charged is ...

  I = $1900×0.08×2 = $304

The finance charge is $304.

__

2. The monthly payment will be the total amount due, divided by the number of months.

  payment = ($1900 +304)/24 = $2204/24 ≈ $91.83

The monthly payment is $91.83.

6 0
3 years ago
Pls help soon:)
Tanzania [10]
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)

Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141


(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71

(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000

</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x

taking "ln" on both sides:
ln(4.797) = ln(1.19)^x

ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)

5 0
3 years ago
Last math problem of the night! Help?? Will give extra points! ​
noname [10]
3y = -x + 3

y= (-1/3)x + 1

perpendicular: 3

y + 1 = 3(x - 6)
y + 1 = 3x - 18

y = 3x - 19
8 0
3 years ago
30 POINTS HELP PLEASE
Reptile [31]

Answer:

\large\boxed{a=-3,\ b=-7\ and\ c=3}

Step-by-step explanation:

ax^2+bx+c=0

We have:

-3a^2=7a-3          <em> subtract 7a from both sides</em>

-3a^2-7a=7a-7a-3

-3a^2-7a=-3           <em>add 3 to both sides</em>

-3a^2-7a+3=-3+3\\\\-3a^2-7a+3=0\to a=-3,\ b=-7, c=3

8 0
3 years ago
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