What is 660/33 reduced ( simplify )

Mathematics

1 answer:

Korvikt [17]3 years ago

5 0

It would be 20/1 ,,20

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Simplify the following fractions by putting them in lowest terms or by performing the indicated operations.

AleksAgata [21]

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My work is in the attached image

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3 years ago

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Klio2033 [76]

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3 years ago

the base of a triangle is 11ft more than the height. if the area is 51ft^2 find the base and the height

nekit [7.7K]

So.. notice the picture below

and thus, we also know, that A = 51, thus

$\bf A=\cfrac{1}{2}bh\implies A=\cfrac{(h+11)h}{2}\implies A=\cfrac{h^2+11h}{2}\qquad A=51
\\\\\\
51=\cfrac{h^2+11h}{2}\implies 102=h^2+11h\implies 0=h^2+11h-102
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\begin{cases}
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\end{cases}$

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and surely you'd know what the base is

7 0

3 years ago

(a^2 - b^2)/(2 + d^3)

Georgia [21]

Answer:

Solving the equation $\frac{a^2-b^2}{2+d^3}$ by putting a=6, b=4 and d=1/2 we get $\frac{160}{17}$

Step-by-step explanation:

We are given formula: $\frac{a^2-b^2}{2+d^3}$

and values a=6, b=4 and d=1/2

We need to put the values of a, b and d in the given equation $\frac{a^2-b^2}{2+d^3}$ and find their result

Putting values in the equation:

$\frac{a^2-b^2}{2+d^3}\\=\frac{(6)^2-(4)^2}{2+(\frac{1}{2})^3}\\=\frac{36-16}{2+\frac{1}{8}}\\=\frac{20}{\frac{2*8+1}{8}}\\=\frac{20}{\frac{17}{8}}\\=\frac{20*8}{17}\\=\frac{160}{17}$

So, solving the equation $\frac{a^2-b^2}{2+d^3}$ by putting a=6, b=4 and d=1/2 we get $\frac{160}{17}$

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3 years ago

|5x + 4| - 10 = -6<br><br> HELP SOLVE THIS FOR ME !!

fredd [130]

Answer: x=0 or x=−8/5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers