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borishaifa [10]
3 years ago
15

Geometry help please

Mathematics
2 answers:
Virty [35]3 years ago
4 0
Let x be the measure of angle BAC. Since this is an isosceles triangle, the measure of BCA is equal to BAC. 

x+x+90 = 180

2x+90-90 = 180-90

2x = 90

2x/2 = 90/2

x = 45

The two angles BAC and BCA are each 45 degrees. This is a 45-45-90 triangle

The answers to part A and B are the same: 45 degrees

-------------------------------------------

For parts C and D, the answers are also the same as well. This is because AB = BC in this isosceles triangle

AC = AB*sqrt(2)

10 = x*sqrt(2)

10/sqrt(2) = x*sqrt(2)/sqrt(2)

x = 10/sqrt(2)

x = 10*(1/sqrt(2))

x = 10*(sqrt(2)/2)

x = 5*sqrt(2)

AB is exactly 5*sqrt(2) units long

AB is approximately 7.0710678 units long

AB = BC so BC is also approximately 7.0710678 units long
xxTIMURxx [149]3 years ago
3 0
 C. length of AB i think so 
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Answer: D

Step-by-step explanation:

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3 years ago
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What is the slope of this line
defon

Answer:

Step-by-step explanation: Do rise and run

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3 years ago
Find the answer pleaseeee...<br><br>-15/9 + 9/4 = ? <br><br>Please find what the question mark is​
SVEN [57.7K]

Answer:

7/12

Step-by-step explanation:

-15/9+9/4

We need to make them have the same denominator:

9x4= 36 so that is our new denominator

-15x4= -60

9x9=81

(Sorry if i dont make sense)

Now we have -60/36+81/36 which is equal to 21/36.

Now we simplify:

21/36=7/12

3 0
3 years ago
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
Can someone pls solve this​
denpristay [2]

Answer:

in triangle PQR, <P - <Q = 20 degrees, <Q - <R = 50 degrees, find <P, <Q, <R

Q = 30, R = 80, P = 50

Step-by-step explanation:

in triangle PQR, <P - <Q = 20 degrees, <Q - <R = 50 degrees, find <P, <Q, <R

R  =  Q +50, 80=30+50

P  =  Q + 20, 50=30+20

Q = 30, R = 80, P = 50

3 0
2 years ago
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