Given:
Markers are sold in packages of 12 and pens are sold in packages of 8.
To find:
Least amount of markers and pens Rick needs to buy to have an equal number of markers and pens
Solution:
To find the least amount of markers and pens, we need to find the LCM of 12 and 8.
Prime factors of 8 and 12 are
To find the LCM, multiply all factors but the common factors are included only once.
Therefore, the least amount of markers and pens Rick needs to buy to have an equal number of markers and pens is 24.
Answer:
it is b the right to evidence lawyer.
Answer:
2, 5, 6
Step-by-step explanation:
The volume of a rectangular prism is given by , where all variables to the right are dimensions of the prism.
Therefore, we're looking for three numbers that multiply to be 60.
Since the question stipulates that no side length may be 10, we have:
To find the weight of 1 load of stone, divide 2/3 by 4.
To divide fractions, use keep change flip.
Keep the first fraction the same, change the division sign into a multiplication sign, and flip the second fraction.
I attached the work and answer for this problem. If you have any questions please feel free to ask.
Hope this helps.
Answer:
graph 1
Step-by-step explanation:
Let's look at graph 1:
The first vertex (the left hand top corner) has a degree 3 because there are 3 line segments coming from it.
Let's check to see if the other vertices have degree 3.
The second vertex (the middle top) has degree 3 because again it has 3 line segments coming from it.
The third vertex (the top right) has degree 3 because it has 3 line segments coming from it.
The fourth vertex (the bottom left) has degree 3 because it has 3 line segments coming from it.
The fifth vertex (the middle bottom) has degree 3 because it has 3 line segments coming from it.
The last vertex (the bottom right) has degree 3 because it has 3 line segments coming from it.
Let's look at graph 2:
The first vertex (top left) has degree 1 because it has one line segment coming from it.
The second vertex( middle top) has degree 2 because it has 2 line segments coming from it.
Graph 2 doesn't have the same degree per vertex.
Looking at graph 3:
The first vertex (top left) has degree 1 while the second (top middle) has degree 2.
Graph 3 doesn't have the same degree per vertex.
Looking at graph 4:
The top left has degree 1. Looking at one of the middle vertices there, they have degree 4 each because they have 4 line segments coming from it. So graph 4 doesn't have the same degree per vertex.
The answer is only graph 1.