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motikmotik
3 years ago
15

In a line of students ,Jenna is number 8.The teacher says the rule for a number pattern is add4.The first term 7.What number sho

uld Jenna say?
Mathematics
1 answer:
balandron [24]3 years ago
4 0
1. You have that the rule for a number pattern is add 4 and the <span>first term is 7.

 2. Let's call "n" to the number in the line where each student is. Then, you can express this as below:

 4n+7

 3. So, you have:

 Student N°1=4(1)+7=11
</span> Student N°2=4(2)+7=15
 Student N°3=4(3)+7=19
 Student N°4=4(4)+7=23
 Student N°5=4(5)+7=27
 Student N°6=4(6)+7=31
 Student N°7=4(7)+7=35
 Student N°8=4(8)+7=39
<span>
 What number should Jenna say?

 The answer is: 39</span>
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pickupchik [31]

So here are a few rules with exponents that you should know:

  1. Multiplying exponents of the same base: x^m*x^n=x^{m+n}
  2. Dividing exponents of the same base: x^m\div x^n=x^{m-n}
  3. Powering a power to a power: (x^m)^n=x^{m*n}
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<h2>1.</h2>

Firstly, solve the outside exponent:

(2x^3y^7)^{-2}=2^{-2}x^{3*-2}y^{7*-2}=2^{-2}x^{-6}y^{-14}

Next, convert the negative exponents into positive ones:

2^{-2}x^{-6}y^{-14}=\frac{1}{2^2x^6y^{14}}=\frac{1}{4x^6y^{14}}

<u>Your final answer is \frac{1}{4x^6y^{14}}</u>

<h2>2.</h2>

For this, just divide:

\frac{12x^5y^3}{4x^{-1}}=\frac{12}{4}x^{5-(-1)}y^{3-0}=3x^6y^3

<u>Your final answer is 3x^6y^3</u>

<h2>3.</h2>

For this, convert all negative exponents into positive ones:

\frac{r^{-7}b^{-8}}{t^{-4}w}=\frac{t^4}{r^7b^8w}

<u>Your final answer is \frac{t^4}{r^7b^8w}</u>

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4 years ago
Solomon has $118 he wants to purchase concert tickets for himself and five friends each tickets cost $19 does he have enough mon
Anon25 [30]
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State the domain of the function.
boyakko [2]
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If we were to plug in y=-2x+5 into a calculator that shows an infinite graph, we would see that the line of the equation would extend both ways infinitely! This means that all real numbers can be inputs for x, because for every x value that exists there is a corresponding y value.

This means that D. All real numbers, is your answer.

Hope it helps! :)
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4 years ago
Please help me answer this question. Show steps and explain
salantis [7]

Your problem statement makes no reference to p or q, so we can only guess that "p/q" refers to the ratio of the lowest- and highest-degree coefficients:

... -6/1

Then the factors of p/q are the factors of 6, with either sign.

Factors of p/q: ±1, ±2, ±3.

There are a number of ways the factors can be tested. To test 1, simply add the coefficients. (The sum is -8.) To test -1, subtract the sum of odd-degree coefficients from the sum of even-degree coefficients. (The difference is 0.)

Knowing that -1 is a root of the function, you can use synthetic division to find the quadratic factor. (See the first attachment for the work.) Then you have ...

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You can continue to test the factors of p/q, or you can factor the quadratic to get ...

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Another way to test the factors is to program your graphing calculator to evaluate the function f(x) for those factors. The result from my TI-84 is shown in the second attachment. That shows f(x) = 0 for x = -3, -1, and +2.

Test the factors: f({-3, -2, -1, 1, 2, 3}) = {0, 4, 0, -8, 0, 24}

This tells you the x-intercepts.

X-intercepts: -3, -1, 2

Of course, the y-intercept is just the constant in the function—the value of the function when x=0.

Y-intercept: -6

As with any odd-degree polynomial with a positive leading coefficient, the overall behavior looks like "/". That is ...

End behaviors: f(x) goes to -∞ as x goes to -∞; f(x) goes to +∞ as x goes to +∞.

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A graph of f(x) is shown in the third attachment. (Graphing calculators make it easy to use graphing to find x-intercepts.)

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