Answer:
Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).
Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).
Step-by-step explanation:
Given : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)
To find : transformed according to the rule 90º , what is the location of q?
Solution : we have given that
vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).
By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )
90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).
Then Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).
counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).
Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).
counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).
then
(notice that as the values of x get smaller and smaller, the graph gets closer and closer to the line y=1);
then
(notice that as the values of x get larger and larger, the graph gets closer and closer to the line y=1).