7) - 1
tan <BAD = BD / AD
BC = √(64 + 36)
BC = √100
BC = 10
now you can solve BD
BD/6 = 6/10
BD = 6*6 / 10
BD = 36/10
BD = 3.6
AD = √36 - 12.96
AD = √23.04
AD = 4.8
tan <BAD = BD / AD
tan <BAD = 3.6 / 4.8
tan <BAD = 0.75
7) - 2
cos <DAC + cos <DAB
as you know cos = Adj / Hypo
cos <DAC = AD/AC
cos <DAC = 4.8 / 8
cos <DAC = 0.6
cos <DAB = AD / AB
cos <DAB = 4.8/6
cos <DAB = 0.8
so
cos <DAC + cos <DAB = 0.6 + 0.8
cos <DAC + cos <DAB = 1.4
hope it helps
The unit depreciation rate can be found by dividing the depreciation base by the estimated useful life, in miles or whatever units happens to be used.
In this case, the depreciation base is 60,000 - 5,000 = $55,000
The useful life is 150,000 miles
The unit depreciation rate, therefore, is 55,000 ÷ 150,000 = $0.367/mile
Answer is C) $0.367 / mile
Answer: Approximately -8.54
Explanation: use Pythagorean’s theorem.
8 squared plus 3 squared equals the resultant squared. 8 squared plus 3 squared is 73, then square root that to get 8.54
Answer:
the monthly payment is 20 dollars. the equation is 300-60= 240 240/12=20
Step-by-step explanation: