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3 years ago

Kendall Swam (n) laps in the pool. Sophia swam 12 less than Kendall. How many laps did they swim altogether.

Mathematics

1 answer:

dezoksy [38]3 years ago

7 0

Kendall and Sophia swam (2n - 12) laps together

<em><u>Solution:</u></em>

Given that, Kendall Swam (n) laps in the pool

To find: Number of laps swam together

From given statement,

Number of laps by Kendall = n

Also, Sophia swam 12 less than Kendall

Therefore, number of laps swam by Sophia is 12 less than the number of laps by Kendall

Number of laps by Sophia = Number of laps by Kendall - 12

Number of laps by Sophia = n - 12

<em><u>How many laps did they swim altogether ?</u></em>

Number of laps swam together = Number of laps by Kendall + Number of laps by Sophia

Number of laps swam together = n + n - 12 = 2n - 12

Thus they swam (2n - 12) laps together

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3 years ago

Find AM, if AM = 6y-4 and MC = 2y+12.

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Step-by-step explanation:

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3 years ago

A line passes through the point (-1,-5) and has a slope of -5.

Anna71 [15]

<h3>hello!</h3>

We're given a point that the line intersects and its slope.

Let's use Point-slope:-

$\boxed{y-y1=m(x-x1)}$

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$\boxed{y-(-5)=-5(x-(-1)}$

$\boxed{y+5=-5(x+1)}$

Convert to slope-intercept:-

$\boxed{y+5=-5x-5}$

$\boxed{y=-5x-5-5}$

Finally,

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2 years ago

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The first 3 terms of the series are

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which amounts to replacing the x with √x in the expansion of cos(√5 x) :

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