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3 years ago

Which is the line shown in the figure?

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

7 0

Answer:

x and z

Step-by-step explanation:

Step2247 [10]3 years ago

3 0

I believe the line shows in XZ because the line segment extends through and past points X and Z :)

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b. Two events are dependent if the occurrence of one event changes to occurrence of the second event. True or False

Naddika [18.5K]

Answer:

true

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

the graph to the right represents mario’s mile time in minutes, y, based on the number of hours he spends training in hours , x

sveta [45]

Answer: it is 13+13=26

Step-by-step explanation:

I don’t care.

3 0

2 years ago

I’m not very sure how to simplify the two bottom rows, can someone help me?

love history [14]

Answer:

The simplification is done below.

Step-by-step explanation:

$(\sin(\frac{\pi}{6})\cos(\frac{\pi}{4}) - \sin(\frac{\pi}{4})\cos(\frac{\pi}{6}))^{2}$

= $(\frac{1}{2} \times \frac{1}{\sqrt{2}} - \frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2})^{2}$

= $((\frac{1}{2\sqrt{2}}) \times (1 - \sqrt{3}))^{2}$

= $0.125 \times (1 - (2 \times \sqrt{3}) +3)$

5 0

3 years ago

Find the t-value such that the area in the right tail is 0.2 with 5 degrees of freedom.

evablogger [386]

Answer:

0.920

Step-by-step explanation:

To calculate this, we proceed to the t-table

Using degree of freedom 5 and significance level of 0.2, the t-value is 0.920

3 0

3 years ago

SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

3 0

3 years ago