By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1 b) p≤1/2 c) s>-1.
I found the complete question on Chegg, here is the full question:
Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1) b) g(p)=√(1-2p) c) m(s)= (s^2+4s+4)/√(s+1)
Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.
a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.
b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.
c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.
Learn more about square root here:
brainly.com/question/3120622
#SPJ4
Answer:
tanI = 
Step-by-step explanation:
We require to calculate GH using Pythagoras' identity in the right triangle.
GH² + GI² = HI²
GH² + 5² = (
)²
GH² + 25 = 95 ( subtract 25 from both sides )
GH² = 70 ( take square root of both sides )
GH = 
Then
tanI = 
= 
=
The correct answer is 20.7 inches of snow
Explanation:
The chart registers the total of snowfall at the school, in this, you can observe the total of snow in December was 3.4 inches, while in January the total was 12.3 and in February it was 8.4. Additionally, if you want to know the total during January and February combined the correct process is to add the two numbers. This means 12.3 inches (January) + 8.4 inches (February) = 20. 7 inches (Total in January and February.) Thus, the answer is 20.7 inches of snow.
<span>The graph of g is the graph of f translated to the left 3 units and down 7 units .</span>
