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erik [133]
2 years ago
6

The length of a rectangular poster is 2 more inches than three times its width. The area of the poster is 33 square inches. Solv

e for the dimensions (length and width) of the poster.
If you give a troll answer, i will report
Mathematics
1 answer:
laiz [17]2 years ago
7 0

Answer:

Step-by-step explanation:

Area of the rectangle = 33 inches sq

Area of a rectangle (formula) = l*b

let the width be x

length = 2 inches + 3x = 2+3x

Area of the rectangle = l*b = 2+3x + x

33 inches sq = 2+3x + x

33 in sq = 2+4x

33/2 = 4x

16.5/4 = x

x = 4.125

width= <u>4.125 inches</u>

length = 2+3x = 2+3(4.125) = <u>14.375</u>

<u></u>

(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)

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In two or more complete sentences, explain how to use ordered pairs of points in x) = 2x + 5 and g(x)=
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see the explanation

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Isolate the variable y

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Let

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<em>Explanation</em>

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