Question

The length of a rectangular poster is 2 more inches than three times its width. The area of the poster is 33 square inches. Solve for the dimensions (length and width) of the poster.
If you give a troll answer, i will report

Answer 1

Answer:

Step-by-step explanation:

Area of the rectangle = 33 inches sq

Area of a rectangle (formula) = l*b

let the width be x

length = 2 inches + 3x = 2+3x

Area of the rectangle = l*b = 2+3x + x

33 inches sq = 2+3x + x

33 in sq = 2+4x

33/2 = 4x

16.5/4 = x

x = 4.125

width= 4.125 inches

length = 2+3x = 2+3(4.125) = 14.375

(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)