Answer:
![\sqrt[4]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E5%7D)
Step-by-step explanation:
A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

Now convert to the radical.
![x^{\frac{5}{4}} = \sqrt[4]{x^5}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%5E5%7D)
Answer:
-40, - 42 and -44
Step-by-step explanation:
The fastes way here is trying. Lets pick a number, intelligently, and then work on it.
We need three even integers that sum -126. These will be all negative numbers and as they are consecutive they will be very similar (for example, -33 and -35 and -37). Thus, lets start by 1/3 of -126, which is -42:
(-42)+ (-44) + (-46) = - 132, so -42 no.
Lets go a step back: -40
(-40) + (-42) + (-44) = -126
So, the integers are -40, -42 and -44
9514 1404 393
Answer:
C. y is 6 less than x
Step-by-step explanation:
It is not hard to check.
A. 6 times x is 6×8 = 48, not 2
B. 6 times y is 6×2 = 12, not 8
C. 6 less than 8 is 2; 6 less than 9 is 3
D. 6 more than 8 is 14, not 2
__
The relation described in C matches the table.
Answer:
(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.
(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.
Step-by-step explanation:
Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.
The probability that a customer makes a purchase is, <em>p</em> = 0.52.
The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.
The probability mass function of <em>X</em> is:

The expected value of a Geometric distribution is:

(a)
Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:


This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.
(b)
Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.
Answer
Buy 2, get 2 free and/or 1/2 off
Step-by-step explanation:
OK, lets say that the tire price was 15. (l)= 15+15=30 (ll)= 15/45%= 33.33x4=133.32 (lll)= 15/2=7.5 7.5x4=30