HURRY 98 POINT!!!! Simplify (23)–2 A. -1/64 B. 1/64 C. 2 D. 64

Harish

Artist 52 [7]

Answer:

Step-by-step explanation:

Distance traveled in $1\frac{4}{5}$ hours = $\frac{3}{10}$

Distance traveled in 1 hour = $\frac{3}{10}$ ÷ $1\frac{4}{5}$

$=\frac{3}{10}$ ÷ $\frac{9}{5}$

$= \frac{3}{10}*\frac{5}{9}\\\\=\frac{1}{2}*\frac{1}{3}\\\\=\frac{1}{6}$

distance traveled in 3 1/5 hours = $\frac{1}{6}*3\frac{1}{5}$

= $=\frac{1}{6}*\frac{8}{5}\\\\=\frac{1}{3}*\frac{4}{5}\\\\=\frac{4}{15}$

5 0

2 years ago

X= 5 10 6 Please help

Lerok [7]

Answer:

x = 6

Step-by-step explanation:

(segment piece) x (segment piece) = (segment piece) x (segment piece)

2*x = 3*4

2x = 12

Divide each side by 2

2x/2 = 12/2

x = 6

8 0

3 years ago

WHAT IS THE LENGTH!!!

Murljashka [212]

The figure is a trapezoid (or trapezium), and the exact length of the trapezoid is 5 units

<h3>How to determine the length?</h3>

The figure is a trapezoid with the following parameters:

Area = 107.95

Base= 12

Height = 12.7

Length = x

The area of a trapezoid is:

Area = 0.5 * (Base + Length) * Height

So, we have:

0.5 * (12 + Length) * 12.7 = 107.95

Evaluate the product

(12 + Length) * 6.35 = 107.95

Divide both sides by 6.35

12 + Length = 17

Subtract 12 from both sides

Length = 5

Hence, the length of the trapezoid is 5 units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

6 0

1 year ago

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

3 years ago

Help me with this problem

siniylev [52]

The answer of your problem is C. Because 25 and 100 are related integers.

5 0

3 years ago

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