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3 years ago

17.

Mathematics

1 answer:

V125BC [204]3 years ago

5 0

Answer:

standard form: 2g²+3g-9

quadratic trinomial

Step-by-step explanation:

standard form: 2g²+3g-9

quadratic trinomial

You might be interested in

Find the reference angle for the given angle. Show your work. -404°

Mamont248 [21]

Answer:

44°

Step-by-step explanation:

The reference angle is the magnitude of the smallest angle between the terminal ray and the x-axis.

Your angle is one full circle clockwise plus 44° more (-360° -44° = -404°), so makes an angle of -44° with respect to the positive x-axis. The magnitude of that is 44°.

_____

<em>Using a function</em>

The attachment shows a calculator function that can be used to find the reference angle for any angle. (Replace the value -404 with the angle of your choice.)

6 0

3 years ago

Read 2 more answers

HELP PLEASE HELP ITS THE LAST QUESTION

andrew-mc [135]

C and d hope it help

7 0

3 years ago

Find the area of each sector. Round your answers to the nearest tenth.

nata0808 [166]

Answer:

Area of sector = 102.6 feet squared

Step-by-step explanation:

Given:

Radius of circle = 14 ft

Angle θ = 60°

Find:

Area of sector

Computation:

Area of sector = [θ/360]πr²

Area of sector = [60/360](22/7)(14)²

Area of sector = [1/6][22/7][196]

Area of sector = 102.6 feet squared

3 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

The sum of four consecutive even integers is 180. what is the smallest integer?

n200080 [17]

42
let the smallest even number be x, than the four even numbers are x, x+2, x+4, x+6, their sum is 180

x+x+2+x+4+x+6=180
4x+12=180
4x=168
x=42
the smallest even number is 42.

3 0

3 years ago