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Vaselesa [24]
4 years ago
5

Which dot plot represents this data set? 14, 15, 14, 19, 15, 15, 19, 12, 12, 12, 15, 17, 11, 17, 16, 18, 18 A. dot plot A B. dot

plot B C. dot plot C D. dot plot D
Mathematics
1 answer:
lisabon 2012 [21]4 years ago
5 0

Answer:

average or the median

Step-by-step explanation:

it is either that or the average which you get by adding all of the nubmers adn dividing by 17

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based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why triang
Svetllana [295]
  <span>AAS since you have two angles and one side. 

LA (never heard of it but if it's actually a theorem then yes. It makes sense in right triangles) 

LL (same as LA) 

HL since the hypotenuse and the leg are congruent. 

SAS CAN be used BUT only if you're going to prove that the sides CE and OQ are congruent or the angles D and P are congruent. You cannot directly apply this. 

ASA CAN be used BUT, as with SAS, can only be used if you prove that either the sides CE and OQ are congruent or the angles D and P are congruent. You cannot directly apply this</span>
7 0
4 years ago
i am a 2 dimensional shape that has four sides. I have four 90 degree angles.i have two sets of parallel lines. i also have two
Roman55 [17]
The answer is 190 for u'r information
6 0
3 years ago
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What is the best next step in the construction of perpendicular bisector of AB?
Serhud [2]

Answer:

I think the answer should be B

4 0
3 years ago
Answer as soon as possible
icang [17]

Answer:

  B.  9, 9x, 18x

Step-by-step explanation:

The value in each box is the product of the row heading and column heading. You can find the missing column heading by dividing the box value (162) by the row heading (18).

7 0
4 years ago
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Find the domain of the function f(t)=√t +3√t
Serjik [45]

Answer:

\mathrm{Domain\:of\:}\:4\sqrt{t}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:t\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

The graph is also attached below.

Step-by-step explanation:

Given the expression

f\left(t\right)=\sqrt{t}\:+3\sqrt{t}

We know that the domain of a function is the set of inputs or argument values for which the function is real and defined.

We know that we can not have a negative value of 't' inside the radicals because if we put any negative number inside the radical expression, it would make the function undefined.

In other words,  the value of t ≥ 0.

Therefore, the function domain is:

\mathrm{Domain\:of\:}\:4\sqrt{t}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:t\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

The graph is also attached below.

7 0
3 years ago
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