<span>AAS since you have two angles and one side.
LA (never heard of it but if it's actually a theorem then yes. It makes sense in right triangles)
LL (same as LA)
HL since the hypotenuse and the leg are congruent.
SAS CAN be used BUT only if you're going to prove that the sides CE and OQ are congruent or the angles D and P are congruent. You cannot directly apply this.
ASA CAN be used BUT, as with SAS, can only be used if you prove that either the sides CE and OQ are congruent or the angles D and P are congruent. You cannot directly apply this</span>
Answer:
I think the answer should be B
Answer:
B. 9, 9x, 18x
Step-by-step explanation:
The value in each box is the product of the row heading and column heading. You can find the missing column heading by dividing the box value (162) by the row heading (18).
Answer:

The graph is also attached below.
Step-by-step explanation:
Given the expression

We know that the domain of a function is the set of inputs or argument values for which the function is real and defined.
We know that we can not have a negative value of 't' inside the radicals because if we put any negative number inside the radical expression, it would make the function undefined.
In other words, the value of t ≥ 0.
Therefore, the function domain is:

The graph is also attached below.