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anastassius [24]

2 years ago

14

i am a 2 dimensional shape that has four sides. I have four 90 degree angles.i have two sets of parallel lines. i also have two

sides that are one length, and my other two sides are a different length.

2 answers:

Roman55 [17]2 years ago

6 0

The answer is 190 for u'r information

Pie2 years ago

3 0

The answer is a rectangle

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Given the following geometric sequence, find the common ratio: {3, 18, 108, ...).

vodomira [7]

Geometric sequences go up due to a common ratio. Here the common ratio can be worked out by dividing a term by its previous term e.g term 2 divided by term 1.

$18/3 = 6
$

Therefore the common ratio is 6.

4 0

2 years ago

Fill in the missing numbers to create equivalent ratios.

jasenka [17]

Step-by-step explanation:

The way to find missing numbers in equivalent ratios is to multiply the means (the first denominator and the second numerator) and multiply the extremes (the first numerator and the second denominator). It sounds really complicated, but it is quite simple =)

2/5 = x/10

The means in this equivalent ration are 5 and x. The extremes are 2 and 10.

5x = 20

Now solve =)

x = 4

That was pretty simple. Let's move on to the next one. Do exactly the same thing here:

4/10 = 6/x

60 = 4x

15 = x

That was pretty simple, too! Keep going!

6/15 = x/25

15x = 150

x = 10

All of these should be equal, so check them by dividing:

2/5 = 0.4

4/10 = 0.4

6/15 = 0.4

10/25 = 0.4

They all check out, so these are your answers: 2/5, 4/10, 6/15, 10/25

I really hope this helps you =)

8 0

3 years ago

Read 2 more answers

Alex got 27 questions out of 30 correct. what present of the questions did he get correct?(use fish method)

Novosadov [1.4K]

if we take 30 to be the 100%, what is 27 off of it in percentage?

$\begin{array}{ccll} amount&\%\\ \cline{1-2} 30 & 100\\ 27& x \end{array} \implies \cfrac{30}{27}=\cfrac{100}{x} \\\\\\ \cfrac{10}{9}=\cfrac{100}{x}\implies 10x=900\implies x=\cfrac{900}{10}\implies x=90$

4 0

1 year ago

A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different tria

Colt1911 [192]

Answer:

The difference in the areas of the cross-sections is 20 m².

Step-by-step explanation:

^^^

6 0

2 years ago

Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

3 0

1 year ago