Select the factors of x^2

(a) Starting with the geometric series [infinity] xn n = 0 , find the sum of the series [infinity] nxn − 1 n = 1 , |x| < 1.

Mila [183]

Let <em>f(x)</em> be the sum of the geometric series,

$f(x)=\displaystyle\frac1{1-x} = \sum_{n=0}^\infty x^n$

for |<em>x</em>| < 1. Then taking the derivative gives the desired sum,

$f'(x)=\displaystyle\boxed{\dfrac1{(1-x)^2}} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}$

5 0

2 years ago

it takes 8 labours 6days to complete a certain job.how many labours would complete the job in 15 days.

VashaNatasha [74]

Answer:

Step-by-step explanation:

Required man days to complete the job = 8 * 6

= 48 Man Days

Required labors to complete the job by 15 days = 48/15

= 3.2

It means, it is required 4 labors can complete the certain work by 15 days

3 0

3 years ago

Please look for the question in the picture.

Ymorist [56]

it will be c

as

negative with negative erased together

5 0

2 years ago

one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt

In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

$\text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A$

⇒ $\text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A$

$= \frac{3-1}{3} A$

$= \frac{2}{3} A$

$\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B$

⇒ $\text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B$

But, Again according to the question,

The total population that claims that they are from A = one half of the total population of A and B.

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B$

⇒ $\frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B$

⇒ $\frac{1}{6} A = \frac{1}{4} B$

⇒ $A =\frac{6}{4}B$

⇒ $\frac{A}{B} =\frac{3}{2}$

8 0

3 years ago

I will give Brainliest to First and Correct Answer. Can Somebody please help...I really need help and I am struggling.

igor_vitrenko [27]

Answer: B' (5,8), C' (3,1)

Step-by-step explanation:

You can use the points A' (-1,8) and A (-2,-3) to find how many units point A was translated.

-2 + 1 = -1

-3 + 11 = 8

Then, you simply add 1 to the x-values of points B and C and 11 to the y-values of points B and C to get B' (5,8), C' (3,1).

I hope this helps!

4 0

2 years ago

Select the factors of x^2 - 12x + 36.